Example 1: Calculating the output current of a transformer
June 2021 · Paper 2P · Question 6(b)(ii)
Question 1
This is a question about a nuclear fusion power station.
The diagram shows how a fusion power station could supply the National Grid in the future.
The fusion power station could supply the input coil of the step-up transformer with a current of 28kA at a voltage of 21kV.
The output coil of the transformer has a voltage of 330kV.
Assume the transformer is 100% efficient.
Calculate the current in the output coil of the transformer.
current = ________ kA
Final answer
For a 100% efficient transformer, input power equals output power:
VinIin = VoutIout 28 × 21 = 330 × Iout Iout = (28 × 21) ÷ 330 = 1.78... kA current = 1.8 kA
Mark scheme points
- M1 Substitute the input and output values into the power equation, VinIin = VoutIout.
- M2 Rearrange the equation to find Iout.
- M3 Calculate the output current as 1.8 kA.
Explanation
At 100% efficiency, the transformer transfers all the input power to the output. Use the given input current and voltages in the power equation, then divide by the output voltage to find the output current.
Iout = (VinIin) ÷ Vout
= (21 kV × 28 kA) ÷ 330 kV
= 1.78... kA
≈ 1.8 kA
The voltage units cancel, leaving the current in kA.
Common mistakes
- Using the output voltage in the numerator instead of dividing the input power by 330 kV.
- Giving a current without the unit kA, or misplacing the decimal point in the calculated value.